Logical Expressions Solutions - D Programming Language
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# Logical Expressions Solutions

#### Logical Expressions Dersi Problem Çözümleri

1. Because the compiler recognizes `10 < value` already as an expression, it expects a comma after it to accept it as a legal argument to `writeln`. Using parentheses around the whole expression would not work either, because this time a closing parenthesis would be expected after the same expression.
2. Grouping the expression as `(10 < value) < 20` removes the compilation error, because in this case first `10 < value` is evaluated and then its result is used with `< 20`.

   We know that the value of a logical expression like `10 < value` is either `false` or `true`. `false` and `true` take part in integer expressions as 0 and 1, respectively. (We will see automatic type conversions in a later chapter.) As a result, the whole expression is the equivalent of either `0 < 20` or `1 < 20`, both of which evaluate to `true`.

3. The expression "greater than the lower value and less than the upper value" can be coded as follows:

           writeln("Is between: ", (value > 10) && (value < 20));

4. "There is a bicycle for everyone" can be coded as `personCount <= bicycleCount` or `bicycleCount >= personCount`. The rest of the logical expression can directly be translated to D from the exercise:

           writeln("We are going to the beach: ",
                   ((distance < 10) && (bicycleCount >= personCount))
                   ||
                   ((personCount <= 5) && existsCar && existsLicense)
                   );

   Note the placement of the `||` operator to help with readability by separating the two main conditions.

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